[Quick 5] What is the Optimal Way to Return a Subset of Properties from a Relationship?

Communities Quick ORM
3

Thanks, Eric.

I messed around with the memento settings. adding includes = [ "product.name", "product.price" ] still returns the entire product model unless I ignoreDefaults=true

Overriding defaults works, but I have to manually specify everything in the Cart model from scratch, which is not ideal.

My current thinking (I need to test it) is that this is a case for setting up dynamic mementifier profiles within the model. So I can do something like this for various API endpoints:

// index
asMemento( profile="simple" );

// new
asMemento( profile="new" );

// show
asMemento( profile="full" );

I’m torn on the idea of offloading memento rules into the model layer, since that feels more like a handler concern to me… but I suppose I could go either way on that.

This is a bit off-topic, but I kept encountering the guardAgainstNotLoaded() error when testing various memento patterns with new, unpersisted, entities with Quick. Bypassing the guard doesn’t work in Quick 5 due to some changes in how relationships work. I created a PR to address the issue with the exception being thrown: Fix Required Parameter Error When Null by homestar9 · Pull Request #209 · coldbox-modules/quick · GitHub

As an added benefit , the above PR fix combined with disabling the loaded guard, should allow developers to use the null object pattern by specifying memento defaults when a relationship is null like this:

// inside a Quick entity
private void function setUpMementifier() {
	super.setupMementifier();
	this.memento.defaults = {
		"product": {}
	};
}